ifft

Function ifft 

Source
pub fn ifft(a: &mut [Complex<f64>])
Examples found in repository?
crates/competitive/src/math/fast_fourier_transform.rs (line 114)
99    fn inverse_transform(mut f: Self::F, len: usize) -> Self::T {
100        let n = len.max(4).next_power_of_two();
101        assert_eq!(f.len(), n / 2);
102        f[0] = Complex::new((f[0].re + f[0].im) * 0.5, (f[0].re - f[0].im) * 0.5);
103        f[n / 4] = f[n / 4].conjugate();
104        let w = Complex::primitive_nth_root_of_unity(n as f64);
105        let mut wk = Complex::<f64>::one();
106        for k in 1..n / 4 {
107            wk *= w;
108            let c = wk.transpose().conjugate() + 1.;
109            let d = c * (f[k] - f[n / 2 - k].conjugate()) * 0.5;
110            f[k] -= d;
111            f[n / 2 - k] += d.conjugate();
112        }
113        bit_reverse(&mut f);
114        ifft(&mut f);
115        let inv = 1. / (n / 2) as f64;
116        (0..len)
117            .map(|i| (inv * if i & 1 == 0 { f[i / 2].re } else { f[i / 2].im }).round() as i64)
118            .collect()
119    }